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Cedarville is a community located within Lawrence Township in Cumberland County. It is part of the Vineland-Millville metro area. It has a total area of total area of 2.3 miles and population around 800.
14 listings with an estimated median price of $217,500
(Data as of 8/8/2022)
The population of the community broken down by age group. The numbers at the top of each bar indicate the number of people in the age bracket below.
Median Age: 38.67
The Temperature chart displays average high and low values for January and July, and is designed to provide an indication of both seasonal and daily temperature variability. The Weather Risk Index indicates the calculated risk of each type of weather event occurring in the future. This risk is based on historical localized storm events and weather patterns. The national average for each type of weather event equals a score of 100, so a score of 200 would represent twice the risk as the national average, and a score of 50 would represent half the risk of the national average.
The Community Educational Index chart is based on the U.S. Census Bureau's Socioeconomic Status (SES) elements. Factors used in creating the index below are income, educational achievement, and occupation of persons within the selected ZIP code. Since this index is based on the population of an entire Zip code, it may not reflect the nature of an individual school.
The Fair Market Rents show average gross rent estimates based on figures provided by the U.S. Department of Housing and Urban Development (HUD).
The Smoking Ban data indicates whether an area has a smoking ban in place for workplaces, restaurants or bars. This information represents that of the search area and may not reflect that of the whole County or State.
The Crime Index compares the risk or probability of future occurrence of certain types of crime in this community as compared to the national average. The national average for each type of crime equals a score of 1.0, so a score of 2.0 would represent twice the risk as the national average, and a score of 0.50 would represent half the risk of the national average.
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